CBSE- Informatics Practices (IP)

CBSE Sample Paper-2020-21

Sample Paper

Marking Scheme

Question Bank

[1 mark questions] Q.NO. 1-21

The avg( ) function in MySQL is an example of ………………….

(i) Math Function

(ii) Text Function

(iii) Date Function

(iv) Aggregate Function

Ans:-

Aggregate Function

The …………. Command can be used to make changes in the rows of table in SQL.

Ans:-

UPDATE

The SQL Command that will display the current time and date.

Ans :-

Select now();

The mid() function in MySql is an example of .

a. Math function

b. Text function

c. Date Function

d. Aggregate Function

Ans:-

b. Text Function

The function is used in SQL to find one string into another.

Ans:-

Instr( )

MID () and SUBSTR () function in SQL serves the same purpose. (Yes/No)

Ans:-

Yes

Write the output for the following SQL command:

Select round(15.193 , -1);

Ans:-

Write a SQL query to display date after 10 days of current date on your system.

Ans:-

Select curdate()+10;

1 mark for correct SQL command

Write the output for the following sql command:

Select SUBSTR(‘ABCDEFG’, -5 ,3)

Ans:-

UBS

10)

Which keyword is used to arrange the result of order by clause in descending order?

a. DSEC

b. DES

c. DESCE

d. DESNO

Ans:-

a. DESC

11)

The clause that is used to arrange the result of SQL command into groups

a. Order by

b. Group in

c. Groups by

d. Group by

Ans :-

d.Group By

12)

Find the Output of SQL command :

select concat (concat (‘Inform’, ‘atics’),‘Practices’);

a. Informatics Practices

b. Informatic Practices

c. Inform practices

d. Inform atics practices

Ans :-

a. InformaticsPractices

13)

Write the output of the following SQL command. select round (19.88,1);

a. 19.88 b. 19.8 c. 19.9 d. 20.0

Ans:-

c. 19.9

14)

The now() function in MySql is an example of .

a. Math function

b. Text function

c. Date Function

d. Aggregate Function

Ans:-

c. Date Function

15)

The………….command can be used to makes changes in the structure of a table in SQL.

Ans:-

ALTER

16)

Write the SQL command that will display the time and date at which the command got executed.

Ans :-

Select sysdate();

17)

Write the output of the following SQL command.

select round(15.872,1);

a. 15.87

b.15.9

c.15.8

d.16

Ans:-

b. 15.9

18)

Manish wants to select all the records from a table named “Students” where the value of the column “FirstName” ends with an “a”. Which of the following SQL statement will do this?

a. SELECT * FROM Students WHERE FirstName = ‘a’;

b. SELECT * FROM Students WHERE FirstName LIKE ‘a%’;

c. SELECT * FROM Students WHERE FirstName LIKE ‘%a’;

d. SELECT * FROM Students WHERE FirstName = ‘%a%’;

Ans:-

d. SELECT * FROM Students WHERE FirstName = ‘%a%’;

19)

The command can be used to add a new column to the table.

Ans:-

ALTER

20)

Which SQL command is used to describe the structure of the table ?

Ans:-

DESC

21)

Foreign Key in a table is used to enforce

i) Data dependency

ii) Referential Integrity

iii) Views

iv) Index Locations

Ans:-

ii) Referential Integrity

22)

A table ‘Student’ contains 5 rows and 4 columns initially. 2 more rows are added and 1 more column is added . What will be the degree and cardinality of the table student after adding these rows and columns?

i) 7, 5

ii) 5,7

iii) 5,5

iv) None of the above

Ans:-

ii) 5,7

23)

Insert into student values(1,’ABC’,’10 Hari Nagar’) is a type of which command :

i) DML

ii) DDL

iii) TCL

iv) DCL

Ans:-

i) DML

24)

What will be the output of - select mid('Pyhton Programming’,3,9);

i) ton Progr

ii) ton Progr

iii) hton Prog

iv) htonProg

Ans:-

iii) hton Prog

25)

Write the output of the following SQL statement:

SELECT TRUNCATE(15.79,-1) , TRUNCATE(15.79,0), TRUNCATE(15.79,1);

a. 15 15 15.7

b. 10 15.7 15.9

c. 10 15 15.7

d. 10 10 15.9

Ans:-

c. 10 15 15.7

26)

The COUNT( ) in MySQL is an example of :

a. Math function

b. Text function

c. Date Function

d. Aggregate Function

Ans:-

d. Aggregate Funcion

27)

…….. which of the following sublanguages of SQL is used to query information from the database and to insert tuples into, delete tuples from and modify tuples in the database?

a. DML

b. DDL

c. Query

d. Relational Schema

Ans:-

a. DML

28)

The ……… clause of SELECT query allows us to select only those rows in the result that satisfied a specified condition.

a. WHERE

b. FROM

c. HAVING

d. LIKE

Ans:-

a. WHERE

29)

Write the output of the following SQL command.

select substr(“COMPUTER”,3,4);

a. MPUT

b. PUTE

c. PU

d. MP

Ans: -

a. MPUT

30)

The now() function in MySql is an example of ___________________.

a. Math function

b. Text function

c. Date Function

d. Aggregate Function

Ans :-

c. Date Function

31)

The _________ command is used to make the changes in a table permanent.

Ans:-

COMMIT

32)

Give SQL command that will display the current month from the date and time.

Ans :-

MONTH( )

33)

Which of the following keywords will you use in the following query to display all the records of students whose name start with S?

SELECT * from student where name “S%”

Ans :-

34)

Which of the following is an aggregate function:

a. Upper()

b. Trim()

c. Date()

d. Sum()

Ans:-

d. SUM()

35)

Write the output of the following SQL command:

SELECT left(“Jammu Region”, 5);

a. Region

b. Jammu

c. Jammu Region

d. None of the above.

Ans:-

b. Jammu

36)

What will be the output of the following code?

SELECT MOD(14,3);

Ans:

37)

What will be the result of the following query based on the table given here.

SELECT COUNT(Salary) FROM Instructor;

Ans:-

COUNT(Salary)

--------------------

38)

Write the command to delete all the data of the table ‘activity’ retaining only structure.

Ans:-

DELETE FROM ACTIVITY;

39)

Write the output for the following SQL commands

Select round(15.193 , -1);

Ans:-

40)

Write a SQL query to display date after 20 days of current date on your system.

Ans:-

SELECT CURDATE( ) + 10;

41)

Write the output for the following sql command

Select SUBSTR(‘ABCDEFG’, -5 ,3)

Ans:-

CDE

42)

Which keyword is used to arrange the result of order by clause in descending order?

a. DSEC

b. DES

c. DESC

d. DESNO

Ans:

C. DESC

43)

Write the output of the following SQL command.

Select round(14.872,1)

a)14.87

b)14.9

c)14.8

d) 15

Ans:-

b) 14.9

44)

The command can be used to change the size of column to the

table.

Ans:-

ALTER

45)

The command can be used to makes changes in the

rows of a table in SQL.

Ans:-

Update

46)

Write the output of the following SQL command.

select round (49.88);

a. 49.88

b. 49.8

c. 49.0

d. 50

Ans:-

d. 50

47)

Write the output of the following SQL command.

select round (19.88,1);

a. 19.88 b. 19.8 c. 19.9 d. 20.0

Ans:-

c. 19.9

48)

Select count(*) from Employee;

The above query will not consider the following:

a) Numeric value b) Text value c) Null value d) Date value

Ans:-

c) NULL Value

49)

Which of the following is/are not correct aggregate functions in SQL:

a. AVG() b) COUNT() c) TOTAL() d) MAX()

Ans:-

c) Total( )

50)

The command can be used to make changes in the definition of a table in SQL.

Ans:-

ALTER

51)

Write the SQL clause used to sort the records of a table.

Ans:-

ORDER BY

52)

Write the output of the following SQL command.

select round(15.857,-1);

a. 15.8

b. 15.9

c. 15.0

d. 20

Ans:-

53)

The now()function in MySql is an example of .

a. Math function

b. Text function

c. Date Function

d. Aggregate Function

Ans:-

c. Date Function

54)

The command can be used to makes changes in the structure of a table in SQL.

Ans:-

ALTER

55)

Write the SQL command that will display the time and date at which the

command got executed.

Ans:

SELECT NOW();

56)

In SQL NULL value means :

(i) 0 value (ii) 1 value (iii) None value (iv) None of the above

Ans:-

iii) None value

57)

Find the output of SQL Query:-

SELECT MOD(11, 3);

Ans:-

58)

The MAX() function in MySql is an example of ___________________.

a. Math function

b. Text function

c. Date Function

d. Aggregate Function

Ans:-

d. Aggregate Function

59)

Write the output of the following SQL command.

select round(314.82,-1);

a. 314.0 b. 310.0 c. 314.8 d. 300.0

Ans:-

d. 300

60)

What will be the output of the following SQL command:

SELECT LTRIM(“ RAJKUMAR “);

Ans:-

“RAJKUMAR “

(Removes spaces from left side)

61)

Write the output of the following SQL command.

select pow(2.37,3.45);

a. 17.62

b. 19.62

c. 18.35

d. 15.82

Ans:-

b. 19.62

62)

Having clause is used with ____________________________function.

a. Math function

b. Text function

c. Date Function

d. Aggregate Function

Ans:-

Aggregate Function

63)

Write the output of the query:

select instr('Toolbarbar','bar');

Ans:-

64)

alter() function in MySql is part of ___________________

a. DDL command

b. DML Command

c. TCL command

Ans

a. DDL Command

1 mark for the correct answer

65)

The ____________command can be used to arrange data in some order in a table in SQL.

Ans:-

ORDER BY

66)

Write the name of the clause used with SELECT command to search for a specific pattern in the strings.

Ans:-

[2 marks questions] Q.NO. 24 - 33

1)	State any two differences between single row functions and multiple row functions. OR What is the difference between the order by and group by clause when used along with the select statement. Explain with an example.
Ans:-	Differences between single row functions and multiple row functions. (i) Single row functions work on one row only whereas multiple row functions group rows (ii) Single row functions return one output per row whereas multiple row functions return only one output for a specified group of rows. OR The order by clause is used to show the contents of a table/relation in a sorted manner with respect to the column mentioned after the order by clause. The contents of the column can be arranged in ascending or descending order. The group by clause is used to group rows in a given column and then apply an aggregate function eg max(), min() etc on the entire group. (any other relevant answer) Single row v/s Multiple row functions 1 mark for each valid point Group by v/s Order by 1 mark for correct explanation 1 mark for appropriate example
2)	Consider the decimal number x with value 8459.2654. Write commands in SQL to: i. round it off to a whole number ii. round it to 2 places before the decimal.
Ans:-	i. select round(8459.2654); ii. select round(8459.2654,-2); 1 mark each for correct answer of part (i) , (ii)
3)	Anjali writes the following commands with respect to a table employee having fields, empno, name, department, commission. *Command1 : Select count() from employee; Command2: Select count(commission) from employee; She gets the output as 4 for the first command but gets an output 3 for the second command. Explain the output with justification.**
Ans:-	This is because the column commission contains a NULL value and the aggregate functions do not take into account NULL values. Thus Command1 returns the total number of records in the table whereas Command2 returns the total number of non NULL values in the column commission.
4)	Consider the following SQL string: “Preoccupied” Write commands to display: a. “occupied” b. “cup” OR Considering the same string “Preoccupied” Write SQL commands to display: a. the position of the substring ‘cup’ in the string “Preoccupied” b. the first 4 letters of the string
Ans:-	a. select substr("Preoccupied", 4); or select substring("Preoccupied", 4); or select mid("Preoccupied",4); or select right(("Preoccupied"”, 8); b. select substr("Preoccupied" ,6,3); or select substring("Preoccupied", 6,3); or select mid(("Preoccupied" ,6,3); OR a. select instr 'Preoccupied' , ‘ 'cup')); b. select left 'Preoccupied',4); 1 mark for each correct answer of part (a) , (b)
5)	What is the difference between the where and Having clause when used along with the select statement. Explain with an example. OR Explain the difference between Update and Alter command with help of an example.
Ans	Where clause is used to apply condition on individual rows and not supports aggregate function While Having clause is used to apply condition on groups and it supports aggregate functions. Eg: SELECT * FROM EMP WHERE SALARY > 50000; Eg: SELECT * FROM EMP GROUP BY DEPTNO HAVING COUNT(*) > 2; OR UPDATE command is a part of DML command and used to update the data of rows of a table. While ALTER command is a part of DDL command and used to change the structure of a table like adding column, removing it or modifying the datatype of columns. Eg: UPDATE EMP SET SALARY = 20000; ALTER EMP ADD EMP_DOJ DATE;
6)	Write the output of following queries:- i. SELECT SUBSTR('Aakila', -3); ii. SELECT LEFT(‘Toolbar’, 4);
Ans:-	I. ‘ila’ II. ‘Tool’
7)	Raghav writes the following commands with respect to a table Flight having Fields FLCODE, START, DESTINATION, NO_STOPS. *Command1 : Select count() from FLIGHT; Command2: Select count(DESTINATION) from FLIGHT; He gets the output as 5 for the first command but gets an output 3 for the second command. Explain the output with justification.**
Ans:-	This is because the column DESTINATION contains a NULL value and the aggregate functions do not take into account NULL values. Thus Command1 returns the total number of records in the table whereas Command2 returns the total number of non NULL values in the column DESTINATION.
8)	Write the output for following queries: i. select MOD(11,4) "Modulus", power(3,2) "Raised"; ii. select CURDATE( )+10; OR i. select length('CORONA COVID-19'); ii. select lcase('COMputer Science');
Ans:-	i. Modulus Raised -------------- ---------- 3 9 ii. currentdate + 10 days aftward date will come or i. 15 ii. ‘computer science’
9)	Consider the decimal number x with value 7459.3654. Write commands in SQL to: i) round it off to a whole number ii)round it to 2 places before the decimal.
Ans:-	(i) select round(7459.3654, 0) (ii) select round(7459.3654, -2)
10)	Shailly writes the following commands with respect to a table Employee having fields, empno, name, department, commission. *Command1 : SELECT COUNT() FROM EMPLOYEE; Command2 : SELECT COUNT(COMMISSION) FROM EMPLOYEE; She gets the output as 7 for the first command but gets an output 5 for the second command. Explain the output with justification.**
Ans:-	This is because the column commission contains a NULL value and the aggregate functions do not take into account NULL values. Thus Command1 returns the total number of records in the table whereas Command2 returns the total number of non NULL values in the column commission.
11)	Consider the following SQL string: “SELFMOTIVATION”. Write commands to display: a. “MOTIVATION” b. “MOT” OR Considering the same string “SELFMOTIVATION”. Write SQL commands to display: a. the position of the substring ‘MOTIV’ in the string “SELFMOTIVATION” b. the last 6 letters of the string
Ans:-	a. select substr(“SELFMOTIVATION”, 5) b. select substr(“SELFMOTIVATION”, 5, 3) OR a. select instr(“SELFMOTIVATION”, “MOTIV”) b. select right(“SELFMOTIVATION”, 6) (student may use other functions like – substring/ mid/ right .. etc
12)	State any two differences between Update and alter commands. OR What is datatype? What are the main objectives of datatypes?
Ans:-	Data types are mean to identify the type of data and its associated functions. The main objectives of datatypes is to clarify the type of data a variable can store and which operations can be performed on it.
13)	Consider the decimal number n with value 278.6975. Write commands in SQL : i. That gives output 279 ii. That gives output 280
Ans:-	i) select round(278.6975); (ii) select round(278.6975,-1); or some other queries that produces same results. 1 mark each for correct answer of part (i) , (ii)
14)	(i) Consider a table “Employee” that have fields - empno, name, department, salary. Based on the above table “Employee”, Manvendra has entered the following SQL command: *SELECT FROM Employee where Salary = NULL; But the Query is not executing successfully. What do you suggest to him in order to execute this query i.e. write the correct query. (ii) Write a SQL query to display the details of those employees whose Salary column has some values.**
Ans:-	(i) select * from Employee where Salary is NULL; (ii) select * from Employee where Salary is not NULL; 1 mark each for correct answer of part (i) , (ii)
15)	Consider the following SQL string: “Master Planner”. Write commands to display: a. “Master” b. “Plan” OR Considering the same string “Master Planner”. Write SQL commands to display: a. the position of the substring ‘Plan’ in the string “Master Planner” b. the Last 4 letters of the string
Ans:-	a. select substr("Master Planner",1,6); b. select substr("Master Planner",8,4); or some other queries that produces same results. 1 mark each for correct answer of part (i) , (ii) OR a. select instr("Master Planner","Plan"); b. select right("Master Planner",4); or some other queries that produces same results. 1 mark each for correct answer of part (i) , (ii)
16)	What are multiple row functions? Give examples OR What is Group by clause? How can we specify condition with Group by clause? Explain with an example.
Ans:-
17)	Consider the decimal number N with value 87654.9876. Write commands in SQL to: i. round it off to a whole number ii. round it to 2 places before the decimal.
Ans:-	Round(87654.9875,0) Round(87654.9875,2)
18)	State any two differences between single row functions and multiple row functions. OR What is the difference between the order by and group by clause when used along with the select statement. Explain with an example.
Ans:-	Differences between single row functions and multiple row functions. (i) Single row functions work on one row only whereas multiple row functions group rows (ii) Single row functions return one output per row whereas multiple row functions return only one output for a specified group of rows. OR The order by clause is used to show the contents of a table/relation in a sorted manner with respect to the column mentioned after the order by clause. The contents of the column can be arranged in ascending or descending order. The group by clause is used to group rows in a given column and then apply an aggregate function eg max(), min() etc on the entire group. (any other relevant answer) Single row v/s Multiple row functions 1 mark for each valid point Group by v/s Order by 1 mark for correct explanation 1 mark for appropriate example
19)	Give the output of : i) Select round(123.93); ii) Select round(123.93,1);
Ans:-	i) 124 ii) 123.9
20)	Consider the following SQL string: “Mental Toughness Helps You Succeed” Write commands to display following using functions: a. “Toughness” b. “Succeed” OR Considering the same string: “Mental Toughness Helps You Succeed” Write SQL commands to display: a. the position of the substring ‘’Helps’ in the string “Mental Toughness Helps You Succeed” the first 6 letters of the string
Ans:-	i) Select mid(‘Mental Toughness Helps You Succeed’, 8, 9) ii) Select right(‘Mental Toughness Helps You Succeed’, 7); OR i) select instr("Mental Toughness Helps You Succeed",’Helps’); ii) select left("Mental Toughness Helps You Succeed",6); 1 Mark each for correct function usage
21)	Find out the error in the following SQL command and correct the same. *Select from employee group by dept where sum(salary) > 2000000**
Ans:-	Select * from employee group by dept where sum(salary) > 2000000 in this query in place of WHERE clause HAVING clause to be used.
22)	Helps Abhay to Compare Having clause and Order by clause? Or Shewani has recently started working in MySQL. Help her in understanding the difference between where and having clause.
Ans:-	Having clause is used in conjunction with group by clause in MySQL. It is used to provide condition based on grouped data. On the other hand, order by clause is an independent clause used to arrange records of a table in either ascending or descending order on the basis of one or more columns OR COUNT(*) returns the number of items in a group, including NULL values and duplicates. COUNT(expression) evaluates expression for each row in a group and returns the number of non null values 2 marks of correct explanation & for any other relevant answer.
23)	Write commands in SQL to: i. round off value 56789.8790 to nearest thousand’s place. ii.Display day from date 13-Apr-2020.
Ans:-	i. Select ROUND(56789.8790,-3); ii. Select DAY(‘2020-04-13’) 1 mark each for correct answer.
24)	Given Table Course: Find out the output for given SQL command: SELECT TID, COUNT(), MIN(FEES) FROM COURSE GROUP BY TID HAVING COUNT()>1;
Ans:-	Ans: TID COUNT(*) MIN(FEES) 101 2 12000 2 marks for correct output
25)	Consider the following SQL strings: S1= “INDIA” S2=”MY” & S3=”DI” Write commands to display: a. “MYINDIA” b. “india” OR Considering the same string as above Write SQL commands to display: a. The position of the string S3 in the string S1. The first 4 letters of the concatenation of string S1 and S2.
Ans:-	a. Select CONCAT(s2,S1); b. Select LCASE(S1) OR a. Select INSTR(S1,S3); b. Select LEFT(CONCAT(S1,S2)); 1 mark each for correct SQL command.
26)	What is importance of primary key in a table? How many primary keys can be there for a table? OR Explain working of TRIM( ) function with proper examples.
Ans:-	Primary Key : A column of collection of columns to identify a tuple in a relation. It is used to search / locate row in a relation. There can be only one primary key in a table. 1 mark for correct definition with proper significance. 1 mark for stating only one primary key in a table. OR TRIM () function is used to remove leading and trailing spaces from a string a table. It can be used as TRIM(String) For example; SELECT TRIM(' bar '); -> 'bar' 1 mark for stating purpose of the functions 1 mark for correct example.
27)	Consider the following ‘Student’ table. (i) What will be the most suitable datatype for the grade column and why? (ii) Write a command to insert Suman’s record with the data as shown in the table.
Ans:-	(i) Gender column datatype char(1) as all the possible values can be accommodated and it will be space efficient. (ii) INSERT INTO Student (Rollno, Sname, Subject, Marks) VALUES (“003”, ”SUMAN”, “IP”, 75); 1 mark for each correct answer
28)	Explain the working of ORDER BY clause of SELECT query with proper example.
Ans:-	The ORDER BY keyword is used to sort the result-set in ascending or descending order. The ORDER BY keyword sorts the records in ascending order by default. To sort the records in descending order, use the DESC keyword. 1 mark for correct explanation. 1 mark for appropriate example
29)	Consider a string “AS YOU know MORE” 2 Write the queries for the following tasks. (i) Write a command to display “know”. (ii) Write a command to display number of characters in the string. OR Consider a string “You Grow more” stored in a column str. What will be the output of the following queries? (i) SELECT UPPER(str); (ii) SELECT substr(str,-9,4);
Ans:-	(i) select mid(“AS YOU know MORE”,8,4); (ii) select length(“AS YOU know MORE”); OR (i) YOU GROW MORE (ii) Grow 1 mark for each correct answer

[3 marks question] Q.NO. 37

Q..1 A relation SALESMAN is given below:

SNO SNAME SALARY BONUS DATEOFJOIN AREA

A01 Kushagra Jain 30000 45.25 29-10-2019 Delhi

A02 Prakhar Sharma 50000 25.50 13-03-2018 Ajmer

B03 Trapti Singh 30000 35.00 18-03-2017 Jhansi

B04 Shailly 80000 45.00 31-12-2018 Delhi

C05 Lakshay Lawania 20000 10.25 23-01-1989 Jaipur

C06 Naresh 70000 12.75 15-06-1987 Ajmer

D07 Krishna Singh 50000 27.50 18-03-1999 Jhansi

Write SQL commands to perform the following operations:

i) Count the number of salesman area-wise.

ii) Display the month name for the date of join of salesman of area ‘Ajmer’

iii) Display the total salary paid to all salesman.

Answers

(i) select area, count(sname) as “Number of salesman” from Salesman group by area;

(ii) select monthname(dateofjoin) from Salesman where area=’Ajmer’;

(iii) select sum(salary) from Salesman;

Q. 2 Given the table CARDEN having following data:

CCode	CarName	Company	Color	Capacity	Charges
501	A-Star	Suzuki	Red	3	14
503	Indigo	Tata	Silver	3	12
502	Innova	Toyota	White	7	15
509	Qualis	Toyota	Silver	4	14
510	Wagon R	Suzuki	Red	4	35

Write SQL Commands for the following :

a. Display the average charges of each type of car company having capacity more than 3.

b. Count the totalcars manufactured by each company.

C. Display the total charges of all the types of vehicles.

Answers:

a. select company, avg(charges) from carden group by company having capacity>3;

b. select Company, count(*) from carden group by Company;

c. Select company, sum(charges) from carden group by company;

Q. 3 Consider a MySQL table ‘product’

P_ID	PROD_NAME	PROD_PRICE	PROD_QTY
P01	Notebook	85	500
P02	Pencil Box	76	200
P03	Water Bottle	129	50
P04	School Bag	739	70

Write SQL Queries to:-

(i) Display maximum PROD_QTY.

(ii) Display the value of each product where the value of each product is calculated as PROD_PRICE * PROD_QTY

(iii) Display average PROD_PRICE.

Answers:

(i) SELECT MAX(PROD_QTY) FROM product;

(ii) SELECT PROD_PRICE*PROD_QTY AS ‘Value’ FROM product;

(iii) SELECT AVG(PROD_PRICE) FROM product;

[5 marks question] – Q.39

Q. 1 Write the SQL functions which will perform the following operations:

i) To display the name of the month of the current date .

ii) To remove spaces from the beginning and end of a string, “ Panorama “.

iii) To display the name of the day eg, Friday or Sunday from your date of birth, dob.

iv) To display the starting position of your first name(fname) from your whole name (name).

v) To compute the remainder of division between two numbers, n1 and n2

Answers:

i) monthname(date(now()))

ii) trim(“ Panaroma “)

iii) dayname(date(dob))

iv) instr(name, fname)

v) mod(n1,n2)

Q. 2 Write the SQL functions which will perform the following operations:

i) To display the name of the month of the current date.

ii) To remove spaces from the beginning and end of a string, “ KV Sangathan “.

iii) To display the name of the day eg, Friday or Sunday from your date of birth, dob.

iv) To print the value of square root of 2 upto 2 decimal points.

v) To compute the remainder of division between two numbers, n1 and n2

Answers:

(i) select month(current_date());

(ii) select trim(“ KV Sangathan “);

(iii) select dayname(dob) from student;

(iv) select round(sqrt(2) , 2);

(v) select n1 % n2;

Q. 3 Write the SQL statement for the following:

i) To display names “Mr. James” and “Ms. Smith” in lower case.

ii) To display current date and time.

iii) To extract date from a given datetime value ‘2020-12-21 09:30:37’.

iv) To remove trailing spaces from string “ Technology Works ”

v) To compute the remainder of division between 125 and 17.

Answers:

(i) select lower(“Mr. James”), lower(“Ms. Smith”);

(ii) select now();

(iii) select date(“2020-12-21 09:30:37”);

(iv) select rtrim(“ Technology Works ”);

(v) select mod(125,17);

Q. 4 Write the SQL functions which will perform the following operations:

i) To display the name of the month of your birthdate .

ii) To remove spaces from the beginning of a string, “ Python“.

iii) To display the day of the week eg, Sunday from current date.

iv) To display the starting 3 characters from your name .

v) To compute the power of 2 to the power 3

Answers:

i) select monthname(‘1998-11-20’);

ii) select ltrim(‘ Python’);

iii) select dayname(now());

iv) select left(‘Nitin’,3);

iv) Select power(2,3);

Q. 1

Consider the table : Shop

Id SName Area Bonus DateofOpen S001 ABC Comp CP 1000.89 2010-11-20

S002 All Infotech GK II 2345.987 2015-09-12

S003 Tech Shoppe CP 761.46 2013-07-25

S004 Geek Tenco Soft NP 456.923 2019-10-10

S005 Hitech Solution GK II 1000.025 2008-12-20

a) Display shop name and bonus after rounding off to zero decimal places.

b) Display the position of occurrence of the string “tech” in shop names.

c) Display three characters from shop name starting from second character.

d) Display the month name for the date of opening of shop

e) Display the name of the shop in all capitals.

Answers:

a) Select Sname,round(Bonus,0) from Shop;

b) Select instr(SName,’tech’) from Shop;

c) Select mid(SName,2,3) from Shop;

d) Select monthname(DateOfOpen) from shop;

e) Select Upper(SName) from shop;

Q. 2 Consider the following table Garments. Write SQL commands for the following statements.

Table : Garments

GCode	GName	Price	MCode	Launch_Date
10001	Formal Shirt	1250	M001	2008-12-12
10020	Frock	750	M004	2007-09-07
10007	Formal Pant	1450	M001	2008-03-09
10024	Denim Pant	1400	M003	2007-04-07
10090	T-Shirt	800	M002	2009-05-12

a) a) To update the Price of Frock to 825.
b)      To print the average price of all the Garments.
c)       To display the Garments Name with their price increased by 15%.
d)      To delete the rows having MCode as M002.
e) To display the details of all the Garments which have GCode less than 10030.

Solutions:

a. Update Garments set price=825 where GName=’Frock’;

b. select avg(price) from Garments;

c. select DName, price*1.15 as ‘Increased_Price’ from Garments;

d. delete from Garments where MCode=’M002’;

e. select * from Garments where GCode<10030;

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